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0=10n^2+11n-21
We move all terms to the left:
0-(10n^2+11n-21)=0
We add all the numbers together, and all the variables
-(10n^2+11n-21)=0
We get rid of parentheses
-10n^2-11n+21=0
a = -10; b = -11; c = +21;
Δ = b2-4ac
Δ = -112-4·(-10)·21
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-31}{2*-10}=\frac{-20}{-20} =1 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+31}{2*-10}=\frac{42}{-20} =-2+1/10 $
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